How Much Work Does The Archer Do On The Bow In Order To Draw The String From X=0 To X=0.60m?
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Work trouble: force vs distance curve for chemical compound bow
- Thread starter Angela_vaal
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Homework Statement
A compound bow in archery allows the user to hold the bowstring at full describe with considerably less force than the maximum force exerted by the cord. The draw force every bit a function of the string position ten for a particular compound bow is shown in (Figure i) .
Part A
How much piece of work does the archer do on the bow in gild to draw the string from x=0 to x=0.60m?
Express your answer to three significant figures and include advisable units.
Homework Equations
area= work
total work=sum of all areas
The Attempt at a Solution
(.2m ten 350 N)/2 + (.3m x 350 N) + (.1m ten 250 N)/ii = 152.5J
153J for iii sig figs.[/B]
Plain the answer is wrong, just I do non know what I did wrong? I found the expanse of the two triangles, and the rectangle in the three equations above.
Answers and Replies
No I do not. Is information technology considering from .5m to .6m it is non a complete triangle?But the area is NOT "two triangles and a rectangle". Do you see why I say that?
Y'all've missed a bit of the area under the bend. Take a closer look at the region of the smaller triangle: what's it "sitting" on?
edit: Ah. Phinds got in in that location before me!
Your thread championship is too general. I've modified it to better place the type of problem.Yous've missed a bit of the area under the curve. Take a closer look at the region of the smaller triangle: what'south it "sitting" on?
edit: Ah. Phinds got in there before me!
the smaller triangle is sitting on a small rectangle between .5m to .6m?
Right.the smaller triangle is sitting on a small rectangle between .5m to .6m?
the smaller triangle is sitting on a small-scale rectangle betwixt .5m to .6m?
That was tricky, merely I got it now. Thanks!!
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